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The electron is a lepton, very similar in structure to the proton and neutron, but differing in the string type used to create its core structure. The lepton family of particles use lepton string, which varies in its dimensional orientation. If you took all the physical dimensions of a hadron string and applied an orthogonal rotation to them... i(x,y,z), you would change it into a lepton string. We can not actually discern the structure of an electron, it appears as a point particle to us because of its manifestation in this alternate set of dimensions (lepton space). Because it generates charge currents in both lepton space and hadron space, we can detect it as a point source of charge. The upper surface of the electron's "leptonic" down quark (green) is the only physical part of the electron that manifests in hadron space. The electron is not a true mirror symmetry of the proton, as it has an orphan string instead of a radical string, in other words the captive (pinned) string of the electron's down quark is also a lepton string. Note that the orphan string is shown enclosing the electron. In the free state, with no external influences to disturb it, this is the way I would expect the electron to arrange its strings. The colors of the quarks are yellow, which represents the leptonic Up quarks, and green for the leptonic Down quark.

If the electron has structure as indicated, that raises the question of the existence of "leptonic neutrons," they should exist, have we detected them? They would be extremely lightweight, probably no more than double the mass of the electron itself if they use orphan strings for PVB's, considerably more massive if they pin hadron strings, but likely to decay much more rapidly in the latter event. These considerations, as well as my conjectures concerning mesons and neutrinos, are probably better left to the professional scientists who have the facilities and resources to test the ideas against reality. A glue gun and wire will only take you so far, heheh. I will watch with interest to see what develops.

Do electrons form shells like the protons? Perhaps, in the nuclear interior, but probably not in free space. If electron shells do form, they will follow the same rules the proton shells do, but all the charge surfaces are of opposite polarity.

Note added 05JUN07: I've been thinking that if electron shells do form, they might not always position themselves in the hollow nuclear interior, they could concievably stack interstitially between hadron shells, causing a reshuffling of the charge distributions of the hadron shells beneath them. If a solution set for a particular heavy isotope cannot be mapped, perhaps it is because of an electron shell muddling up the underlying solution sets.

Note Added 14APR10: I have recently had a minor epiphany concerning superconductors and the formation of Cooper pairs. I used to believe that Cooper pairs were discreet electrons sharing a pinned vector boson between them. I no longer believe that to be the case. The captive photon (radical string) would tend to tangle in the metallic lattice, it would be prone to absorbing thermal energy causing the string to grow, essentially it would still incur resistance unless the shared string was kept very short. It occurred to me that at the cold temperatures and in the high energy-density medium of the metallic solid, the electrons may very well form into an electron shell of two (identical in structure to the proton shell of two, but having its structure in lepton space). The solved structure of the two electron shell would have no pinned vector bosons, hence no external strings to tangle with the lattice structure in the superconductor to cause resistance. Properties of the material encourage the electrons to form into shells of two particles, but it is the lack of pinned vector bosons that allows these pairs to flow through the material without resistance.

Copyright 2000 by Arnold J. Barzydlo
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